Divisor Sum of 527

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Example of Divisor Sum of Integer

$\map {\sigma_1} {527} = 576$

where $\sigma_1$ denotes the divisor sum function.


Proof

From Divisor Sum of Integer: Corollary

$\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$

where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.


We have that:

$527 = 17 \times 31$


Hence:

\(\ds \map {\sigma_1}{527}\) \(=\) \(\ds \paren {17 + 1} \paren {31 + 1}\)
\(\ds \) \(=\) \(\ds 18 \times 32\)
\(\ds \) \(=\) \(\ds \paren {2 \times 3^2} \times \paren {2^5}\)
\(\ds \) \(=\) \(\ds 2^6 \times 3^2\)
\(\ds \) \(=\) \(\ds \paren {2^3 \times 3}^2\)
\(\ds \) \(=\) \(\ds 24^2\)
\(\ds \) \(=\) \(\ds 576\)

$\blacksquare$