Divisor Sum of 6435

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Example of Divisor Sum of Integer

$\map {\sigma_1} {6435} = 13 \, 104$

where $\sigma_1$ denotes the divisor sum function.


Proof

We have that:

$6435 = 3^2 \times 5 \times 11 \times 13$


Hence:

\(\ds \map {\sigma_1} {6435}\) \(=\) \(\ds \dfrac {3^3 - 1} {3 - 1} \times \paren {5 + 1} \times \paren {11 + 1} \times \paren {13 + 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds \dfrac {26} 2 \times 6 \times 12 \times 14\)
\(\ds \) \(=\) \(\ds 13 \times 6 \times 12 \times 14\)
\(\ds \) \(=\) \(\ds 13 \times \paren {2 \times 3} \times \paren {2^2 \times 3} \times \paren {2 \times 7}\)
\(\ds \) \(=\) \(\ds 2^4 \times 3^2 \times 7 \times 13\)
\(\ds \) \(=\) \(\ds 13 \, 104\)

$\blacksquare$