Divisor Sum of 6825

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Example of Divisor Sum of Integer

$\map {\sigma_1} {6825} = 13 \, 888$

where $\sigma_1$ denotes the divisor sum function.


Proof

We have that:

$6825 = 3 \times 5^2 \times 7 \times 13$


Hence:

\(\ds \map {\sigma_1} {6825}\) \(=\) \(\ds \paren {3 + 1} \times \dfrac {5^3 - 1} {5 - 1} \times \paren {7 + 1} \times \paren {13 + 1}\) Divisor Sum of Integer
\(\ds \) \(=\) \(\ds 4 \times \dfrac {124} 4 \times 8 \times 14\)
\(\ds \) \(=\) \(\ds 4 \times 31 \times 8 \times 14\)
\(\ds \) \(=\) \(\ds 2^2 \times 31 \times 2^3 \times \paren {2 \times 7}\)
\(\ds \) \(=\) \(\ds 2^6 \times 7 \times 31\)
\(\ds \) \(=\) \(\ds 13 \, 888\)

$\blacksquare$