Divisor Sum of 8085
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Example of Divisor Sum of Integer
- $\map {\sigma_1} {8085} = 16 \, 416$
where $\sigma_1$ denotes the divisor sum function.
Proof
We have that:
- $8085 = 3 \times 5 \times 7^2 \times 11$
Hence:
\(\ds \map {\sigma_1} {8085}\) | \(=\) | \(\ds \paren {3 + 1} \times \paren {5 + 1} \times \dfrac {7^3 - 1} {7 - 1} \times \paren {11 + 1}\) | Divisor Sum of Integer | |||||||||||
\(\ds \) | \(=\) | \(\ds 4 \times 6 \times \dfrac {342} 6 \times 12\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 4 \times 6 \times 57 \times 12\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^2 \times \paren {2 \times 3} \times \paren {3 \times 19} \times \paren {2^2 \times 3}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^5 \times 3^3 \times 19\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 16 \, 416\) |
$\blacksquare$