Double Angle Formulas/Hyperbolic Sine/Proof 2
Jump to navigation
Jump to search
Theorem
- $\sinh 2 x = 2 \sinh x \cosh x$
Proof
\(\ds \sinh 2 x\) | \(=\) | \(\ds \frac 1 2 \paren {e^{2 x} - e^{-2 x} }\) | Definition of Hyperbolic Sine | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac 1 2 \paren {e^x + e^{-x} } \paren {e^x - e^{-x} }\) | Difference of Two Squares | |||||||||||
\(\ds \) | \(=\) | \(\ds 2 \paren {\frac{e^x + e^{-x} } 2 \cdot \frac {e^x - e^{-x} } 2}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2 \sinh x \cosh x\) | Definition of Hyperbolic Sine, Definition of Hyperbolic Cosine |
$\blacksquare$