Four Fours/Lemmata/Three Fours/27/Solutions

Puzzle: Three Fours: $27$

Using exactly $3$ instances of the number $4$, the task is to write an expression for $27$, using whatever arithmetical operations you consider necessary.

Solutions

Solution $1$

$27 = 4! + \sqrt {\dfrac 4 {. \dot 4} }$