Fundamental Theorem of Calculus for Contour Integrals/Corollary
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Theorem
Let $D \subseteq \C$ be an open set.
Let $f: D \to \C$ be a continuous function.
Suppose that $F: D \to \C$ is an antiderivative of $f$.
Let $\gamma: \closedint a b \to D$ be a contour that consists of one directed smooth curve.
Then the contour integral:
- $\ds \int_\gamma \map f z \rd z = \map F {\map \gamma b} - \map F {\map \gamma a}$
Proof
By the chain rule:
- $\dfrac \d {\d t} \map F {\map \gamma t} = \map {F'} {\map \gamma t} \map {\gamma'} t = \map f {\map \gamma t} \map {\gamma'} t$
Thus:
\(\ds \int_\gamma \map f z \rd z\) | \(=\) | \(\ds \int_a^b \map f {\map \gamma t} \map {\gamma'} t \rd t\) | Definition of Antiderivative | |||||||||||
\(\ds \) | \(=\) | \(\ds \int_a^b \frac \d {\d t} \map F {\map \gamma t} \rd t\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map F {\map \gamma b} - \map F {\map \gamma a}\) | Fundamental Theorem of Calculus |
$\blacksquare$