Henry Ernest Dudeney/Modern Puzzles/195 - Domino Groups/Solution

Modern Puzzles by Henry Ernest Dudeney: $195$

Domino Groups

If the dominoes are laid out in the manner shown in the diagram and I then break the line into $4$ lengths of $7$ dominoes each,

it will be found that the sum of the pips in the first group is $49$, in the second $34$, in the third $46$, and in the fourth $39$.

Now I want to play them out so that all the four groups of seven when the line is broken shall contain the same number of pips.

Can you find a way of doing it?

Solution

This is one way to do it:

Sources

• 1926: Henry Ernest Dudeney: Modern Puzzles ... (previous) ... (next): Solutions: $195$. -- Domino Groups
• 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $484$. Domino Groups