Henry Ernest Dudeney/Modern Puzzles/24 - Simple Arithmetic/Solution
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Modern Puzzles by Henry Ernest Dudeney: $24$
- "Simple" Arithmetic
- Two gentlemen with an eccentric approach to philosophy were pinned down by your investigative reporter.
- They wished to riddle my mathematical understanding.
- "Our two ages combined," said the first, "is $44$."
- "Don't be silly," said the other, "it's $1280$."
- They looked at me and said, "You see, we didn't tell you how we were combining them."
- It was clear to me that the first number was their difference and the second was their product.
- Now, how old were these two gentlemen?
Solution
- $20$ and $64$.
Proof
Let their ages be $a$ and $b$.
Then:
\(\ds a - b\) | \(=\) | \(\ds 44\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds a\) | \(=\) | \(\ds b + 44\) | |||||||||||
\(\ds a b\) | \(=\) | \(\ds 1280\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds \paren {b + 44} b\) | \(=\) | \(\ds 1280\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds b^2 + 44 b - 1280\) | \(=\) | \(\ds 0\) |
You can either factorise $1280$ into its two factors which differ by $44$, which brings us no further than where we started from, or we use the Quadratic Formula to smash this exquisite gem with a mallet:
- $b = \dfrac {-44 \pm \sqrt {44^2 + 4 \times 1280} } 2 = -22 \pm 42$
and we can pick out what we want from the debris.
$\blacksquare$
Sources
- 1926: Henry Ernest Dudeney: Modern Puzzles ... (previous) ... (next): Solutions: $24$. -- "Simple" Arithmetic
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $35$. "Simple" Arithmetic