Hero's Method/Examples/92

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Examples of Use of Hero's Method

The calculation of the square root of $92$ by Hero's Method proceeds as follows:

\(\ds x_0\) \(=\) \(\ds 8 \cdotp 5\) as the initial approximation
\(\ds \leadsto \ \ \) \(\ds x_1\) \(=\) \(\ds \dfrac {8.5 + \frac {92} {8 \cdotp 5} } 2\)
\(\ds \) \(=\) \(\ds 10 \cdotp 8235\)
\(\ds \leadsto \ \ \) \(\ds x_2\) \(=\) \(\ds \dfrac {10 \cdotp 8235 + \frac {92} {10 \cdotp 8235} } 2\)
\(\ds \) \(=\) \(\ds 9 \cdotp 66176 \dots\)
\(\ds \leadsto \ \ \) \(\ds x_3\) \(=\) \(\ds \dfrac {9 \cdotp 66176 \dots + \frac {92} {9 \cdotp 66176 \dots} } 2\)
\(\ds \) \(=\) \(\ds 9 \cdotp 9519 \dots\)

and so on.

The actual value of $\sqrt {92}$ is:

$\sqrt {92} \approx 9.5917$

$\blacksquare$


Sources