Image of Element under Cartesian Product of Subsets
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Theorem
Let $S$ and $T$ be sets.
Let $A \subseteq S$ and $B \subseteq T$.
Let $\RR$ be the relation defined by the Cartesian product $A \times B$.
Then:
- $\forall x \in A: \map \RR x = B$
Proof
We have:
\(\ds \forall x \in A: \, \) | \(\ds \map \RR s\) | \(=\) | \(\ds \set {t \in T: \tuple {s, t} \in \RR}\) | Definition of Image of Element under Relation | ||||||||||
\(\ds \) | \(=\) | \(\ds \set {t \in T: \tuple {s, t} \in A \times B}\) | Definition of $\RR$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {t \in T: s \in A, t \in B}\) | Definition of Cartesian Product | |||||||||||
\(\ds \) | \(=\) | \(\ds \set {t \in T: t \in B}\) | as $s \in A$ | |||||||||||
\(\ds \) | \(=\) | \(\ds B\) | as $B \subseteq T$ |
$\blacksquare$