# Image of Path is Path-Connected Set

## Theorem

Let $T = \left({S, \tau}\right)$ be a topological space.

Let $I \subset \R$ be the closed real interval $\closedint a b$.

Let $\gamma: I \to S$ be a path.

Then:

- $\map \gamma I$ is a path-connected set of $T$.

## Proof

From Path-Connected iff Path-Connected to Point, $\map \gamma I$ is a path-connected set if and only if every point of $\map \gamma I$ is path-connected to a common point.

It is shown that every point of $\map \gamma I$ is path-connected to $\map \gamma a$.

Let $H = \map \gamma I$.

Let $x = \map \gamma a$.

From Point is Path-Connected to Itself, $x$ is path-connected to itself.

Let $y$ be any element of $H \setminus \set x$.

By assumption:

- $\exists t \in \hointl a b : \map \gamma t = y$

From Continuity of Composite with Inclusion, $\mathbin {\gamma} {\restriction_{\closedint a t}} : \closedint a t \to H$ is a continuous mapping.

It follows that $\mathbin {\gamma} {\restriction_{\closedint a t}}$ is a path joining $x$ to $y$.

The result follows.

$\blacksquare$