Image of Union under Relation/General Result
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Theorem
Let $S$ and $T$ be sets.
Let $\RR \subseteq S \times T$ be a relation.
Let $\powerset S$ be the power set of $S$.
Let $\mathbb S \subseteq \powerset S$.
Then:
- $\ds \RR \sqbrk {\bigcup \mathbb S} = \bigcup_{X \mathop \in \mathbb S} \RR \sqbrk X$
Proof
\(\ds t\) | \(\in\) | \(\ds \RR \sqbrk {\bigcup \mathbb S}\) | ||||||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists s \in \bigcup \mathbb S: \, \) | \(\ds t\) | \(\in\) | \(\ds \map \RR s\) | Image of Subset under Relation equals Union of Images of Elements | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists X \in \mathbb S: \exists s \in X: \, \) | \(\ds t\) | \(\in\) | \(\ds \map \RR s\) | Definition of Union of Set of Sets | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds \exists X \in \mathbb S: \, \) | \(\ds t\) | \(\in\) | \(\ds \RR \sqbrk X\) | Definition of Image of Subset under Relation | |||||||||
\(\ds \leadstoandfrom \ \ \) | \(\ds t\) | \(\in\) | \(\ds \bigcup_{X \mathop \in \mathbb S} \RR \sqbrk X\) | Definition of Union of Set of Sets |
$\blacksquare$