Integration by Parts/Corollary
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Corollary to Integration by Parts
Let $u$ and $v$ be real functions which are integrable on their domain.
Then:
- $\ds \int u v \rd x = \paren {\int u \rd x} v - \int \paren {\int u \rd x} \dfrac {\d v} {\d x} \rd x$
Proof
From Integration by Parts:
- $(1): \quad \ds \int u \dfrac {\d v} {\d x} \rd x = u v - \int v \dfrac {\d u} {\d x} \rd x$
In $(1)$, let us make the identifications:
\(\text {(2)}: \quad\) | \(\ds u\) | \(\gets\) | \(\ds v\) | ||||||||||||
and: | |||||||||||||||
\(\ds \dfrac {\d v} {\d x}\) | \(\gets\) | \(\ds u\) | |||||||||||||
\(\text {(3)}: \quad\) | \(\ds \leadsto \ \ \) | \(\ds v = \int \dfrac {\d v} {\d x} \rd x\) | \(\gets\) | \(\ds \int u \rd x\) |
This gives:
\(\ds \int u v \rd x\) | \(=\) | \(\ds \int v \cdot u \rd x\) | changing order for clarity | |||||||||||
\(\ds \) | \(=\) | \(\ds v \int u \rd x - \int \paren {\int u \rd x} \dfrac {\d v} {\d x} \rd x\) | substituting from $(2)$ and $(3)$ |
$\blacksquare$
Sources
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of Mathematical Functions ... (previous) ... (next): $3$: Elementary Analytic Methods: $3.3$ Rules for Differentiation and Integration: Integration by Parts: $3.3.13$