Law of Identity/Formulation 1/Proof by Truth Table

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Theorem

$p \vdash p$


Proof

We apply the Method of Truth Tables (trivially) to the proposition.

$\begin{array}{|c|c|} \hline p & p \\ \hline \F & \F \\ \T & \T \\ \hline \end{array}$

$\blacksquare$