Law of Identity/Formulation 1/Proof by Truth Table
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Theorem
- $p \vdash p$
Proof
We apply the Method of Truth Tables (trivially) to the proposition.
$\begin{array}{|c|c|} \hline p & p \\ \hline \F & \F \\ \T & \T \\ \hline \end{array}$
$\blacksquare$