Measure of Half-Open Interval as Difference of Distribution Function
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Theorem
Let $a, b \in \R$.
Let $\mu$ be a finite Borel measure on $\R$.
Let $F_\mu$ be the distribution function of $\mu$.
Then:
- $\map \mu {\hointl a b} = \map {F_\mu} b - \map {F_\mu} a$
Proof
Note that:
- $\map \mu {\hointl {-\infty} a} < \infty$
since $\mu$ is finite.
Then, we have:
\(\ds \map {F_\mu} b - \map {F_\mu} a\) | \(=\) | \(\ds \map \mu {\hointl {-\infty} b} - \map \mu {\hointl {-\infty} a}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \mu {\hointl {-\infty} b \setminus \hointl {-\infty} a}\) | Measure of Set Difference with Subset | |||||||||||
\(\ds \) | \(=\) | \(\ds \map \mu {\hointl a b}\) | Difference of Unbounded Closed Intervals |
$\blacksquare$
Sources
- 2013: Donald L. Cohn: Measure Theory (2nd ed.) ... (previous) ... (next): $1.3$: Outer Measures