Norm in terms of Normed Dual Space
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Theorem
Let $\GF \in \set {\R, \C}$.
Let $\struct {X, \norm {\, \cdot \,} }$ be a normed vector space over $\GF$.
Let $X^\ast$ be the normed dual of $X$.
Let $B_{X^\ast}^-$ be the closed unit ball of $X^\ast$.
Then:
- $\ds \norm x = \sup_{f \in B_{X^\ast}^-} \cmod {\map f x}$
Proof
From Fundamental Property of Norm on Bounded Linear Functional, we have:
- $\ds \cmod {\map f x} \le \norm x$
for each $x \in X$.
From Existence of Support Functional, there exists $f \in B_{X^\ast}^-$ such that $\map f x = \norm x$.
Hence we conclude:
- $\ds \norm x = \sup_{f \in B_{X^\ast}^-} \cmod {\map f x}$
$\blacksquare$