P-adic Numbers is Hausdorff Topological Space

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Theorem

Let $p$ be a prime number.

Let $\struct {\Q_p, \norm {\,\cdot\,}_p}$ be the $p$-adic numbers.

Let $\tau_p$ be the topology induced by the non-Archimedean norm $\norm {\,\cdot\,}_p$.


Then the topological space $\struct{\Q_p, \tau_p}$ is Hausdorff.


Proof 1

Let $d_p$ be the metric induced by the norm $\norm {\,\cdot\,}_p$.

By definition of the topology induced by the non-Archimedean norm $\norm {\,\cdot\,}_p$, $\tau_p$ is the topology induced by the metric $d_p$.

From Metric Space is Hausdorff, it follows that $\struct{\Q_p, \tau_p}$ is Hausdorff.

$\blacksquare$


Proof 2

Let $x, y \in \Q_p$ such that $x \ne y$.

By Non-Archimedean Norm Axiom $\text N 1$: Positive Definiteness:

$r := \norm {x - y}_p > 0$

Then, for all $z\in\Q_p$ we have:

\(\ds \max\set {\norm {x - z}_p, \norm {z - y}_p}\) \(\ge\) \(\ds \norm {(x-z) + (z-y)} _p\) Non-Archimedean Norm Axiom $\text N 4$: Ultrametric Inequality
\(\ds \) \(=\) \(\ds \norm {x - y} _p\)
\(\ds \) \(=\) \(\ds r\)

Therefore, the $r$-open balls $\map {B_r} x$ and $\map {B_r} y$ are disjoint.

$\blacksquare$