Powers of Disjoint Permutations
Jump to navigation
Jump to search
Theorem
Let $S_n$ denote the symmetric group on $n$ letters.
Let $\rho, \sigma$ be disjoint permutations.
Then:
- $\forall k \in \Z: \paren {\sigma \rho}^k = \sigma^k \rho^k$
Proof
A direct application of Power of Product of Commutative Elements in Group, and the fact that Disjoint Permutations Commute.
$\blacksquare$
Sources
- 1996: John F. Humphreys: A Course in Group Theory ... (previous) ... (next): Chapter $9$: Permutations: Proposition $9.8$