Primitive of Reciprocal of a squared minus x squared squared/Also presented as

Primitive of Reciprocal of a squared minus x squared squared: Also presented as

This result is also seen presented in the form:

$\ds \int \frac {\d x} {\paren {a^2 - x^2}^2} = \frac x {2 a^2 \paren {a^2 - x^2} } + \frac 1 {2 a^2} \int \frac {\d x} {a^2 - x^2}$

Sources

• 1968: George B. Thomas, Jr.: Calculus and Analytic Geometry (4th ed.) ... (previous) ... (next): Front endpapers: A Brief Table of Integrals: $19$.