Primitive of Reciprocal of x squared plus a squared/Examples/16 + x^2

From ProofWiki
Jump to navigation Jump to search

Example of Use of Primitive of $\dfrac 1 {x^2 + a^2}$

$\ds \int \dfrac 1 {16 + x^2} \rd x = \dfrac 1 4 \arctan \dfrac x 4 + C$


Proof

From Primitive of $\dfrac 1 {x^2 + a^2}$:

$\ds \int \frac {\d x} {x^2 + a^2} = \frac 1 a \arctan \frac x a + C$


The result follows by setting $a = 4$.

$\blacksquare$


Sources