Probability of Continuous Random Variable Lying in Singleton Set is Zero
Theorem
Let $\struct {\Omega, \Sigma, \Pr}$ be a probability space.
Let $X$ be a continuous real variable on $\struct {\Omega, \Sigma, \Pr}$.
Then, for each $x \in \R$, we have:
- $\map \Pr {X \le x} = \map \Pr {X < x}$
In particular:
- $\map \Pr {X = x} = 0$
Corollary
Let $C$ be a countable subset of $\R$.
Then:
- $\map \Pr {X \in C} = 0$
Proof
Let $F_X$ be the cumulative distribution function of $X$ so that:
- $\map {F_X} x = \map \Pr {X \le x}$
for each $x \in \R$.
Let $P_X$ be the probability distribution of $X$.
Since $X$ is a continuous real variable, we have:
- $F_X$ is continuous.
From Sequential Continuity is Equivalent to Continuity in the Reals, we have:
- for each real sequence $\sequence {x_n}_{n \mathop \in \N}$ converging to $x$, we have $\map {F_X} {x_n}\to \map {F_X} x$.
For each $n \in \N$, let:
- $\ds x_n = x - \frac 1 n$
We have that $x_n \to x$, so:
- $\ds \map {F_X} x = \lim_{n \mathop \to \infty} \map {F_X} {x - \frac 1 n}$
We also have that $\sequence {x_n}_{n \mathop \in \N}$ is a increasing sequence.
So, we have:
- $\ds \hointl {-\infty} {x - \frac 1 n} \subseteq \hointl {-\infty} {x - \frac 1 {n + 1} }$
for each $n \in \N$.
So:
- $\ds \sequence {\hointl {-\infty} {x - \frac 1 n} }_{n \mathop \in \N}$ is a increasing sequence of sets.
We can see that:
- $\ds \bigcup_{n \mathop = 1}^\infty \hointl {-\infty} {x - \frac 1 n} = \openint {-\infty} x$
Lemma
Let $x$ be a real number.
Then:
- $\ds \bigcup_{n \mathop = 1}^\infty \hointl {-\infty} {x - \frac 1 n} = \openint {-\infty} x$
$\Box$
So, we have:
\(\ds \map \Pr {X < x}\) | \(=\) | \(\ds \map {P_X} {\openint {-\infty} x}\) | Definition of Probability Distribution | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \map {P_X} {\hointl {-\infty} {x - \frac 1 n} }\) | Measure of Limit of Increasing Sequence of Measurable Sets | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \map \Pr {X \le x - \frac 1 n}\) | Definition of Probability Distribution | |||||||||||
\(\ds \) | \(=\) | \(\ds \lim_{n \mathop \to \infty} \map {F_X} {x - \frac 1 n}\) | Definition of Cumulative Distribution Function | |||||||||||
\(\ds \) | \(=\) | \(\ds \map {F_X} x\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Pr {X \le x}\) | Definition of Cumulative Distribution Function |
We then have:
\(\ds \map \Pr {X \le x}\) | \(=\) | \(\ds \map \Pr {\set {X = x} \cup \set {X < x} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map \Pr {X = x} + \map \Pr {X < x}\) | Probability of Union of Disjoint Events is Sum of Individual Probabilities |
giving:
- $\map \Pr {X = x} = 0$
$\blacksquare$
Also see
- Distribution Function of Finite Signed Borel Measure is Continuous iff Measure is Diffuse - of which this result is an instantiation with a similar proof