Ratio of Proton Moment to Nuclear Magneton

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Theorem

The ratio of the proton moment to the nuclear magneton is given by:

\(\ds \dfrac {\mu_{\mathrm p} } {\mu_{\mathrm N} }\) \(=\) \(\ds 2 \cdotp 79284 \, 73446 \, 3(82)\)


Proof

We have:

\(\ds \mu_{\mathrm N}\) \(=\) \(\ds 5 \cdotp 05078 \, 3699 \, (31) \times 10^{-27} \, \mathrm {J \, T^{-1} }\) Definition of Nuclear Magneton
\(\ds \mu_{\mathrm p}\) \(=\) \(\ds 1 \cdotp 41060 \, 67973 \, 6 \, (60) \times 10^{-26} \, \mathrm {J \, T^{-1} }\) Definition of Proton Moment
\(\ds \leadsto \ \ \) \(\ds \dfrac {\mu_{\mathrm p} } {\mu_{\mathrm N} }\) \(=\) \(\ds 2 \cdotp 79284 \, 73446 \, 3 \, (82)\) by calculation

$\blacksquare$


Sources

which gives the mantissa as $2 \cdotp 792 \, 782$, with an uncertainty of $\pm 17$ corresponding to the $2$ least significant figures