Ring of Integers of Number Field is Free Z-Module
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Theorem
Let $K$ be an algebraic number field.
Let $\OO_K$ be its ring of integers.
Let $\sqbrk {K : \Q}$ denote the degree of field extension $K : \Q$.
Then $\OO_K$ is a free $\Z$-module of dimension $\sqbrk {K : \Q}$.
Proof
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Sources
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- 2011: J.S. Milne: Algebraic Number Theory: Chapter $2$ Ring of Integers: Rings of integers are finitely generated: Proposition $2.29$