Set of Subsemigroups forms Complete Lattice

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Theorem

Let $\struct {S, \circ}$ be a semigroup.

Let $\mathbb S$ be the set of all subsemigroups of $S$.


Then:

$\struct {\mathbb S, \subseteq}$ is a complete lattice.

where for every set $\mathbb H$ of subsemigroups of $S$:

the infimum of $\mathbb H$ necessarily admitted by $\mathbb H$ is $\ds \bigcap \mathbb H$.


Proof

From Semigroup is Subsemigroup of Itself:

$\struct {S, \circ} \in \mathbb S$

Let $\mathbb H$ be a non-empty subset of $\mathbb S$.

Let $T = \bigcap \mathbb H$.

Then:

\(\ds a, b\) \(\in\) \(\ds T\)
\(\ds \leadsto \ \ \) \(\ds \forall K \in \mathbb H: \, \) \(\ds a, b\) \(\in\) \(\ds K\) Definition of Set Intersection
\(\ds \leadsto \ \ \) \(\ds \forall K \in \mathbb H: \, \) \(\ds a \circ b\) \(\in\) \(\ds K\) Subsemigroups are closed
\(\ds \leadsto \ \ \) \(\ds a \circ b\) \(\in\) \(\ds T\) Definition of Set Intersection

Hence, from Set of Subsets which contains Set and Intersection of Subsets is Complete Lattice:

$\struct {\mathbb S, \subseteq}$ is a complete lattice

where $\ds \bigcap \mathbb H$ is the infimum of $\mathbb H$.

$\blacksquare$