Solutions of cos x equals cos a/Proof
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Theorem
Let $\alpha \in \closedint {-1} 1$ be fixed.
Let:
- $(1): \quad \cos x = \cos \alpha$
The solution set of $(1)$ is:
- $\set {x \in \R: \forall n \in \Z: x = 2 n \pi \pm \alpha}$
Proof
From Cosine of Supplementary Angle:
- $\map \cos {\pi - x} = -\cos x$
and so from Real Cosine Function is Periodic:
\(\ds x\) | \(=\) | \(\ds 2 n \pi \pm a\) |
$\blacksquare$
Sources
- 1953: L. Harwood Clarke: A Note Book in Pure Mathematics ... (previous) ... (next): $\text V$. Trigonometry: General solution of $\cos x = \cos \alpha$