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Combined display of all available logs of ProofWiki. You can narrow down the view by selecting a log type, the username (case-sensitive), or the affected page (also case-sensitive).
- 19:08, 28 November 2019 LaSTLeGioNTR talk contribs created page Talk:Producer of Dedekind Cut/Examples (Created page with "Sorry, I forget to add "Definition". Can anyone delete this page please? :( # LaSTLeGioNTR (talk) 22:07, 28 Nov 19 (GMT+3)")
- 19:00, 28 November 2019 LaSTLeGioNTR talk contribs created page Definition:Producer of Dedekind Cut/Examples/sqrt2 (Created page with "== Examples of Producers of Dedekind Cuts == <onlyinclude> Let $L = \{l\in\Q: l < \sqrt{2}\}$ and $R = \{r\in\Q: \sqrt{2}<r\}$. Then $...")
- 18:59, 28 November 2019 LaSTLeGioNTR talk contribs created page Definition:Producer of Dedekind Cut/Examples/2 (Created page with "== Examples of Producers of Dedekind Cuts == <onlyinclude> Let $L = \{l\in\Q: l \leq 2\}$ and $R = \{r\in\Q: 2<r\}$. Then $(L, R)$ is...")
- 18:58, 28 November 2019 LaSTLeGioNTR talk contribs created page Definition:Producer of Dedekind Cut/Examples (Created page with "== Examples of Producers of Dedekind Cuts == <onlyinclude> === Example: 2 === {{:D...")
- 18:50, 28 November 2019 LaSTLeGioNTR talk contribs created page Producer of Dedekind Cut/Examples/sqrt2 (Created page with "== Examples of Producers of Dedekind Cuts == <onlyinclude> Let $L = \{l\in\Q: l < sqrt{2}\}$ and $R = \{r\in\Q: sqrt{2}<r\}$. Then $(L...")
- 18:47, 28 November 2019 LaSTLeGioNTR talk contribs created page Producer of Dedekind Cut/Examples/2 (Created page with "== Examples of Producers of Dedekind Cuts == <onlyinclude> Let $L = \{l\in\Q: l \leq 2\}$ and $R = \{r\in\Q: 2<r\}$. Then $(L, R)$ is a...")
- 18:38, 28 November 2019 LaSTLeGioNTR talk contribs created page Producer of Dedekind Cut/Examples (Created page with "== Examples of Producers of Dedekind Cuts ==")
- 18:33, 28 November 2019 LaSTLeGioNTR talk contribs created page Definition:Producer of Dedekind Cut (Created page with "== Definition == Let $\struct {S, \preceq}$ be a totally ordered set and $S'\subseteq S$. Let $(L,R)$ be a Definition:Dedekind_Cut| dedek...")