Square of Sample Correlation Coefficient is no greater than 1
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Definition
Let $S$ be a set of paired observations of a statistic from a population.
The sample correlation coefficient $r$ of $S$ satisfies the inequality:
- $r^2 \le 1$
Proof
Let $\ds \bar x = \frac 1 n \sum_{i \mathop = 1}^n x_i$ and $\ds \bar y = \frac 1 n \sum_{i \mathop = 1}^n y_i$.
\(\ds r^2\) | \(=\) | \(\ds \frac {\paren {s_{x y} }^2} {s_{xx} s_{yy} }\) | Definition of Sample Correlation Coefficient | |||||||||||
\(\ds \) | \(=\) | \(\ds \frac {\ds \paren {\sum_{i \mathop = 1}^n \paren {x_i - \bar x} \paren {y_i - \bar y} }^2} {\ds \paren {\sum_{i \mathop = 1}^n \paren {x_i - \bar x}^2} \paren {\sum_{i \mathop = 1}^n \paren {y_i - \bar y}^2} }\) | ||||||||||||
\(\ds \) | \(\le\) | \(\ds \frac {\ds \paren {\sum_{i \mathop = 1}^n \paren {x_i - \bar x} \paren {y_i - \bar y} }^2} {\ds \paren {\sum_{i \mathop = 1}^n \paren {x_i - \bar x} \paren {y_i - \bar y} }^2}\) | Cauchy's Inequality | |||||||||||
\(\ds \) | \(=\) | \(\ds 1\) |
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): Cauchy-Schwarz inequality: $(2)$
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): Cauchy-Schwarz inequality: $(2)$