Student's t-Distribution with One Degree of Freedom is Standard Cauchy Distribution
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Theorem
The Student's $t$-distribution with one degree of freedom is a special case of a standard Cauchy distribution.
Proof
Let $X$ be a continuous random variables with a Student's $t$-distribution with one degree of freedom.
Then $X$ has probability density function:
- $\map {f_X} x = \dfrac {\map \Gamma {\frac {k + 1} 2} } {\sqrt {\pi k} \map \Gamma {\frac k 2} } \paren {1 + \dfrac {x^2} k}^{-\frac {k + 1} 2}$
where $k = 1$.
Hence:
\(\ds \map {f_X} x\) | \(=\) | \(\ds \dfrac {\map \Gamma {\frac {1 + 1} 2} } {\sqrt {\pi \times 1} \map \Gamma {\frac 1 2} } \paren {1 + \dfrac {x^2} 1}^{-\frac {1 + 1} 2}\) | setting $k = 1$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac {\map \Gamma 1} {\sqrt \pi \paren {1 + x^2} \map \Gamma {\frac 1 2} }\) | simplifying | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {\sqrt \pi \paren {1 + x^2} \map \Gamma {\frac 1 2} }\) | Gamma Function Extends Factorial: $\map \Gamma 1 = 1$ | |||||||||||
\(\ds \) | \(=\) | \(\ds \dfrac 1 {\pi \paren {1 + x^2} }\) | Gamma Function of One Half: $\map \Gamma {\frac 1 2} = \sqrt \pi$ |
which is exactly the standard Cauchy distribution.
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): Cauchy distribution
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): Cauchy distribution