Sum of Cosines of 2 k pi over 5

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Theorem

\(\ds \) \(\) \(\ds 1 + \cos \dfrac {2 \pi} 5 + \cos \dfrac {4 \pi} 5 + \cos \dfrac {6 \pi} 5 + \cos \dfrac {8 \pi} 5\)
\(\ds \) \(=\) \(\ds 1 + \cos 72 \degrees + \cos 144 \degrees + \cos 216 \degrees + \cos 288 \degrees\)
\(\ds \) \(=\) \(\ds 0\)


Proof

Let $z_1, z_2, \dotsc, z_5$ be the complex $5$th roots of unity.

From Sum of Powers of Primitive Complex Roots of Unity, setting $s = 1$:

$z_1 + z_2 + z_3 + z_4 + z_5 = 0$

Thus from Complex 5th Roots of Unity:

$1 + \cis 72 \degrees + \cis 144 \degrees + \cis 216 \degrees + \cis 288 \degrees = 0$

Equating the real parts:

$1 + \cos 72 \degrees + \cos 144 \degrees + \cos 216 \degrees + \cos 288 \degrees = 0$


Sum of Cosines of 2 k pi over 5.png

$\blacksquare$


Sources