Talk:Operating on Transitive Relationships Compatible with Operation
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No, that's not it. The point here is really about how transitivity strengthens compatibility. The reflexive closure stuff is there because we want to prove that $a < b$ and $c \le d$ implies not only $a \circ c \le b \circ d$ but actually $a \circ c < b \circ d$, but transitivity is what lets us do that neat trick of taking the group product on both sides of two inequalities, rather than just an inequality and an equation. --Dfeuer (talk) 10:59, 12 January 2013 (UTC)
Perhaps there's a way to separate those aspects cleanly? --Dfeuer (talk) 11:00, 12 January 2013 (UTC)