Tamura-Kanada Circuit Method/Example

Example of Use of Tamura-Kanada Circuit Method

Starting with $A = X = 1$, $B = \dfrac 1 {\sqrt 2}$, $C = \dfrac 1 4$, the successive values of $\dfrac {\paren {A + B}^2} {4 C}$ on the first $3$ loops are:

\(\text {(1)}: \quad\)

\(\ds \)

\(\)

\(\ds 2 \cdotp 91421 \, 35\)

\(\text {(2)}: \quad\)

\(\ds \)

\(\)

\(\ds 3 \cdotp 14057 \, 97\)

\(\text {(3)}: \quad\)

\(\ds \)

\(\)

\(\ds 3 \cdotp 14159 \, 28\)

and it is seen that the value for $\pi$ is already correct to $6$ decimal places.

Sources

• 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $3 \cdotp 14159 \, 26535 \, 89793 \, 23846 \, 26433 \, 83279 \, 50288 \, 41972 \ldots$
• 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $3 \cdotp 14159 \, 26535 \, 89793 \, 23846 \, 26433 \, 83279 \, 50288 \, 41971 \ldots$