Three Points Describe a Circle

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Let $A$, $B$ and $C$ be points which are not collinear.

Then there exists exactly one circle whose circumference passes through all $3$ points $A$, $B$ and $C$.


As $A$, $B$ and $C$ are not collinear, the triangle $ABC$ can be constructed by forming the lines $AB$, $BC$ and $CA$.

The result follows from Circumscribing Circle about Triangle.