Problem of Apollonius/Points
Classic Problem
Let there be three points in the plane which are not collinear.
It is required to draw a circle passing through each of the three points.
Solution
Let the points be $A$, $B$ and $C$.
As $A$, $B$ and $C$ are not collinear, the triangle $ABC$ can be constructed by forming the lines $AB$, $BC$ and $CA$.
Proof
Follows from Circumscribing Circle about Triangle.
$\blacksquare$
Source of Name
This entry was named for Apollonius of Perga.
Historical Note
The Problem of Apollonius was originally posed, and apparently solved, by Apollonius of Perga in his work Tangencies.
The cases of $3$ points and $3$ straight lines were given by Euclid in his Elements: Book $\text {IV}$.
The case of the $3$ circles was interesting enough to attract the attention of a number of mathematicians of the $17$th century, including Isaac Newton and François Viète.
It was supposedly solved by Elisabeth of the Palatinate during the course of a series of mathematical discussions with René Descartes sometime around or after $1641$.
While this in itself is a remarkable feat, the fact that she achieved it using Descartes' own methods makes it more impressive, as these are not the easiest tools to use to attack the problem.
However, Descartes appears to have been unfairly and cruelly dismissive of her achievement
Sources
- 1986: David Wells: Curious and Interesting Numbers ... (previous) ... (next): $3$
- 1992: George F. Simmons: Calculus Gems ... (previous) ... (next): Chapter $\text {A}.6$: Apollonius (ca. $\text {262}$ – $\text {190}$ B.C.)
- 1997: David Wells: Curious and Interesting Numbers (2nd ed.) ... (previous) ... (next): $3$
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): Problem of Apollonius
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): problem of Apollonius