Uniformly Convergent Series of Continuous Functions is Continuous
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Theorem
Let $\sequence {f_n}$ be a sequence of real functions.
Let each of $\sequence {f_n}$ be continuous on the interval $\hointr a b$.
![]() | This article, or a section of it, needs explaining. In particular: Investigation needed as to whether there is a mistake in 1992: Larry C. Andrews: Special Functions of Mathematics for Engineers (2nd ed.) -- should it actually be a closed interval? You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by explaining it. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Explain}} from the code. |
Let the series:
- $\ds \map f x := \sum_{n \mathop = 1}^\infty \map {f_n} x$
be uniformly convergent for all $x \in \closedint a b$.
![]() | This article, or a section of it, needs explaining. In particular: Is $f$ really defined at $x=b$? What are the domains of $\sequence {f_n}$? You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by explaining it. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Explain}} from the code. |
Then $f$ is continuous on $\hointr a b$.
Proof
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Sources
- 1992: Larry C. Andrews: Special Functions of Mathematics for Engineers (2nd ed.) ... (previous) ... (next): $\S 1.3.1$: Properties of uniformly convergent series: Theorem $1.9 \ \text{(a)}$