Union of Derivatives is Subset of Derivative of Union
Jump to navigation
Jump to search
Theorem
Let $T = \struct {S, \tau}$ be a topological space.
Let:
- $\FF \subseteq \powerset S$ be a set of subsets of $S$
where $\powerset S$ denotes the power set of $S$.
Then:
- $\ds \bigcup_{A \mathop \in \FF} A' \subseteq \paren {\bigcup_{A \mathop \in \FF} A}'$
where $A'$ denotes the derivative of $A$.
Proof
Let $\ds x \in \bigcup_{A \mathop \in \FF} A'$.
Then by definition of union there exists $A \in \FF$ such that:
- $(1): \quad x \in A'$
- $\ds A \subseteq \bigcup_{A \mathop \in \FF} A$
Then by Derivative of Subset is Subset of Derivative:
- $\ds A' \subseteq \paren {\bigcup_{A \mathop \in \FF} A}'$
Hence by $(1)$ the result:
- $\ds x \in \paren {\bigcup_{A \mathop \in \FF} A}'$
follows by definition of subset.
$\blacksquare$
Sources
- Mizar article TOPGEN_1:34