2665

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Number

$2665$ (two thousand, six hundred and sixty-five) is:

$5 \times 13 \times 41$

The $1$st term of the $4$th triplet of consecutive positive integers all of which are sphenic:

$2665 = 5 \times 13 \times 41$, $2666 = 2 \times 31 \times 43$, $2667 = 3 \times 7 \times 127$

The $12$th Fermat pseudoprime to base $3$ after $91$, $121$, $286$, $671$, $703$, $949$, $1105$, $1541$, $1729$, $1891$, $2465$:

$3^{2665} \equiv 3 \pmod {2665}$

Also see

• Previous  ... Next: Triples of Consecutive Sphenic Numbers
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