Acceleration of Point in Plane in Intrinsic Coordinates
Jump to navigation
Jump to search
Theorem
Let $\mathbf a$ be the acceleration of a particle $P$ in space.
Let $P$ be moving in a plane $\PP$.
Then the motion of $P$ can be expressed in intrinsic coordinates as:
- $\mathbf a = \dfrac {\d \map v t} {\d t} \mathbf s + \dfrac {\paren {\map v t}^2} \rho \bspsi$
where:
- $\mathbf s$ denotes the unit vector along the tangential direction of $P$
- $\bspsi$ denotes the unit vector toward the center of curvature of the motion of $P$
- $\map v t$ is the speed of $P$ at the time $t$
- $\rho$ is the radius of curvature of the motion of $P$ at time $t$.
Proof
![]() | This theorem requires a proof. In particular: Needs some more background work on intrinsic coordinates for this to make sense See https://dspace.mit.edu/bitstream/handle/1721.1/60691/16-07-fall-2004/contents/lecture-notes/d4.pdf You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by crafting such a proof. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{ProofWanted}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): acceleration
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): acceleration