Biconditional Elimination/Sequent Form/Proof 1/Form 1

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Theorem

$p \iff q \vdash p \implies q$


Proof

By the tableau method of natural deduction:

$p \iff q \vdash p \implies q$
Line Pool Formula Rule Depends upon Notes
1 1 $p \iff q$ Premise (None)
2 1 $p \implies q$ Biconditional Elimination: $\iff \EE_1$ 1

$\blacksquare$