Cardinality of Set Union/General Case
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Theorem
Let $\sequence {S_n}_{n \mathop \in \N}$ be a sequence of sets.
Then:
\(\ds \card {\bigcup_{i \mathop = 1}^n S_i}\) | \(=\) | \(\ds \sum_{i \mathop = 1}^n \card {S_i}\) | ||||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \sum_{1 \mathop \le i \mathop < j \mathop \le n} \card {S_i \cap S_j}\) | |||||||||||
\(\ds \) | \(\) | \(\, \ds + \, \) | \(\ds \sum_{1 \mathop \le i \mathop < j \mathop < k \mathop \le n} \card {S_i \cap S_j \cap S_k}\) | |||||||||||
\(\ds \) | \(\) | \(\ds \cdots\) | ||||||||||||
\(\ds \) | \(\) | \(\, \ds + \, \) | \(\ds \paren {-1}^{n - 1} \card {\bigcap_{i \mathop = 1}^n S_i}\) |
Proof
By Cardinality is Additive Function, we can apply the Inclusion-Exclusion Principle:
If $f: \SS \to \R$ is an additive function, then:
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\(\ds \map f {\bigcup_{i \mathop = 1}^n S_i}\) | \(=\) | \(\ds \sum_{i \mathop = 1}^n \map f {S_i}\) | ||||||||||||
\(\ds \) | \(\) | \(\, \ds - \, \) | \(\ds \sum_{1 \mathop \le i \mathop < j \mathop \le n} \map f {S_i \cap S_j}\) | |||||||||||
\(\ds \) | \(\) | \(\, \ds + \, \) | \(\ds \sum_{1 \mathop \le i \mathop < j \mathop < k \mathop \le n} \map f {S_i \cap S_j \cap S_k}\) | |||||||||||
\(\ds \) | \(\) | \(\ds \cdots\) | ||||||||||||
\(\ds \) | \(\) | \(\, \ds + \, \) | \(\ds \paren {-1}^{n - 1} \map f {\bigcap_{i \mathop = 1}^n S_i}\) |
$\blacksquare$
Sources
- 1965: J.A. Green: Sets and Groups ... (previous) ... (next): Chapter $1$. Sets: Exercise $4$