# Characterization of Integrable Functions

## Theorem

Let $\struct {X, \Sigma, \mu}$ be a measure space.

Let $f: X \to \overline \R, f \in \MM_{\overline \R}$ be a $\Sigma$-measurable function.

Then the following are equivalent:

- $(1): \quad f \in \map {\LL_{\overline \R} } \mu$, that is, $f$ is $\mu$-integrable.
- $(2): \quad$ The positive and negative parts $f^+$ and $f^-$ are $\mu$-integrable.
- $(3): \quad$ The absolute value $\size f$ of $f$ is $\mu$-integrable.
- $(4): \quad$ There exists an $\mu$-integrable function $g: X \to \overline \R$ such that $\size f \le g$ pointwise.

This page has been identified as a candidate for refactoring of advanced complexity.In particular: Several results here, making specific referencing impreciseUntil this has been finished, please leave
`{{Refactor}}` in the code.
Because of the underlying complexity of the work needed, it is recommended that you do not embark on a refactoring task until you have become familiar with the structural nature of pages of $\mathsf{Pr} \infty \mathsf{fWiki}$.To discuss this page in more detail, feel free to use the talk page.When this work has been completed, you may remove this instance of `{{Refactor}}` from the code. |

## Proof

We prove the whole cycle of implications:

- $(1) \implies (2) \quad$ by definition of $(1)$

- $(2) \implies (3)\quad$ because $\size f = f^+ + f^-$ and Integral of Positive Measurable Function is Additive

- $(3) \implies (4)\quad$ because $g:= \size f$ exists

It remains to demonstrate $(4) \implies (1)$.

Let $f \in \MM_{\overline \R}$ and $g$ according to $(4)$.

Then:

- $f = f^+ - f^-$

where $f^+$ is the positive and $f^-$ is the negative part of $f$.

We have that $f^+$ and $f^-$ are positive and measurable.

Let $f^0$ stand for either $f^+$ or $f^-$.

We have that:

- $\size f = f^+ + f^-$

Therefore:

- $f^0 \le \size f \le g$

It is to be shown that the Integral of Positive Measurable Function of $f^0$ exists and is finite.

Let $\EE^+$ and $\map {I_\mu} h$ be defined as in Integral of Positive Measurable Function.

Then:

- $\forall h \in \EE^+$: $h \le f^0 \implies h \le g$

Hence:

- $\set {h: h \le f^0, h \in \EE^+} \subseteq \set {h: h \le g, h \in \EE^+}$

- $\ds \int f^0 \rd \mu := \sup \set {\map {I_\mu} h: h \le f^0, h \in \EE^+} \le \sup \set {\map {I_\mu} h: h \le g, h \in \EE^+} < \infty$

We have that the integrals for $f^+$ and $f^-$ both are finite.

Therefore $f$ is $\mu$-integrable according to definition.

$\blacksquare$

This article needs to be linked to other articles.In particular: The steps in the above need to be demonstrated and explained by linking to appropriate results on $\mathsf{Pr} \infty \mathsf{fWiki}$ As it stands, none of the above can be followed without knowing all about this subject.You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by adding these links.To discuss this page in more detail, feel free to use the talk page.When this work has been completed, you may remove this instance of `{{MissingLinks}}` from the code. |

.

## Sources

- 2005: René L. Schilling:
*Measures, Integrals and Martingales*... (previous) ... (next): $10.3$