Characterization of Paracompactness in T3 Space/Lemma 20
This article needs proofreading. Please check it for mathematical errors. If you believe there are none, please remove {{Proofread}} from the code.To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Proofread}} from the code. |
Theorem
Let $T = \struct{X, \tau}$ be a topological space.
Let every open cover of $T$ be even.
Let $\tau_{X \times X}$ denote the product topology on the cartesian product $X \times X$.
Let $N$ be a neighborhood of the diagonal $\Delta_X$ of $X \times X$ in the product space $\struct {X \times X, \tau_{X \times X} }$.
Then there exists an open neighborhood $W$ of the diagonal $\Delta_X$ in $\struct {X \times X, \tau_{X \times X} }$:
- $W$ is symmetric as a relation on $X \times X$, that is, $W = W^{-1}$
- the composite relation $W \circ W$ is a subset of $N$, that is, $W \circ W \subseteq N$
Proof
Let:
- $\VV = \set{V \in \tau : V \times V \subseteq N}$
From Neighborhood of Diagonal induces Open Cover:
- $\VV$ is an open cover of $T$
We have by hypothesis, $\VV$ is even.
From Characterization of Even Cover, there exists an open neighborhood $R$ of the diagonal $\Delta_X$ in $\struct {X \times X, \tau_{X \times X} }$:
- $\set{\map R x : x \in S}$ is a refinement of $\VV$
where:
By definition of refinement of cover:
- $\forall x \in X : \exists V \in \VV : \map R x \subseteq V$
From Cartesian Product of Subsets:
- $\forall x \in X : \exists V \in \VV : \map R x \times \map R x \subseteq V \times V$
From Subset Relation is Transitive:
- $\forall x \in X : \map R x \times \map R x \subseteq N$
Let $W = R \cap R^{-1}$, where $R^{-1}$ is the inverse relation of $R$ on $X \times X$.
From Inverse of Open Set in Product Space is Open in Inverse Product Space:
- $R^{-1}$ is open in $\struct {X \times X, \tau_{X \times X}}$
By Open Set Axiom $\paren {\text O 2 }$: Pairwise Intersection of Open Sets:
- $W$ is open in $\struct {X \times X, \tau_{X \times X}}$
From Inverse of Reflexive Relation is Reflexive:
- $R^{-1}$ is reflexive
From Intersection of Reflexive Relations is Reflexive:
- $W$ is reflexive
By definition of reflexive:
- $W$ is an open neighborhood of the diagonal $\Delta_X$.
From Intersection of Relation with Inverse is Symmetric Relation:
- $W$ is a symmetric relation on $X \times X$
We have:
\(\ds \forall x, y, z \in X: \, \) | \(\ds \tuple{y,z} \in \map W x \times \map W x\) | \(\leadsto\) | \(\ds y, z \in \map W x\) | Definition of Cartesian Product | ||||||||||
\(\ds \) | \(\leadsto\) | \(\ds \tuple{x, y}, \tuple{x, z} \in W\) | Definition of Image of Element under Relation | |||||||||||
\(\ds \) | \(\leadsto\) | \(\ds \tuple{x, y}, \tuple{x, z} \in R\) | Intersection is Subset and Definition of Subset | |||||||||||
\(\ds \) | \(\leadsto\) | \(\ds y, z \in \map R x\) | Definition of Image of Element under Relation | |||||||||||
\(\ds \) | \(\leadsto\) | \(\ds \tuple{y, z} \in \map R x \times \map R x\) | Definition of Cartesian Product | |||||||||||
\(\ds \) | \(\leadsto\) | \(\ds \tuple{y, z} \in N\) | Definition of Subset |
By definition of subset:
- $\forall x \in X : \map W x \times \map W x \subseteq N$
From Composition of Symmetric Relation with Itself is Union of Products of Images:
- $W \circ W = \ds \bigcup_{x \in X} \map W x \times \map W x$
From Union of Subsets is Subset:
- $W \circ W \subseteq N$
$\blacksquare$
Sources
- 1955: John L. Kelley: General Topology: Chapter $5$: Compact Spaces: $\S$Paracompactness: Lemma $30$