Chebyshev Distance on Real Vector Space is Metric

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The Chebyshev distance on $\R^n$:

$\displaystyle \forall x, y \in \R^n: d_\infty \left({x, y}\right):= \max_{i \mathop = 1}^n {\left\vert{x_i - y_i}\right\vert}$

is a metric.

Proof 1

This is an instance of the Chebyshev distance on the cartesian product of metric spaces $A_1, A_2, \ldots, A_3$.

This is proved in Chebyshev Distance is Metric.


Proof 2

Proof of $M1$

\(\displaystyle \map {d_\infty} {x, x}\) \(=\) \(\displaystyle \max_{i \mathop = 1}^n \size {x_i - x_i}\) Definition of $d_\infty$
\(\displaystyle \) \(=\) \(\displaystyle 0\)

So axiom $M1$ holds for $d_\infty$.


Proof of $M2$

Let $k \in \closedint 1 n$ such that:

\(\displaystyle \size {x_k - z_k}\) \(=\) \(\displaystyle \max_{i \mathop = 1}^n \size {x_i - z_i}\)
\(\displaystyle \) \(=\) \(\displaystyle \map {d_\infty} {x, z}\)

Then by the Triangle Inequality for Real Numbers:

$\size {x_k - z_k} \le \size {x_k - y_k} + \size {y_k - z_k}$

But by the nature of the $\max$ operation:

$\displaystyle \size {x_k - y_k} \le \max_{i \mathop = 1}^n \size {x_i - y_i}$


$\displaystyle \size {y_k - z_k} \le \max_{i \mathop = 1}^n \size {y_i - z_i}$


$\displaystyle \size {x_k - y_k} + \size {y_k - z_k} \le \max_{i \mathop = 1}^n \size {x_i - y_i} + \max_{i \mathop = 1}^n \size {y_i - z_i}$


$\map {d_\infty} {x, z} \le \map {d_\infty} {x, y} + \map {d_\infty} {y, z}$

So axiom $M2$ holds for $d_\infty$.


Proof of $M3$

\(\displaystyle \map {d_\infty} {x, y}\) \(=\) \(\displaystyle \max_{i \mathop = 1}^n \size {x_i - y_i}\) Definition of $d_\infty$
\(\displaystyle \) \(=\) \(\displaystyle \max_{i \mathop = 1}^n \size {y_i - x_i}\) Definition of Absolute Value
\(\displaystyle \) \(=\) \(\displaystyle \map {d_\infty} {y, x}\) Definition of $d_\infty$

So axiom $M3$ holds for $d_\infty$.


Proof of $M4$

Let $x = \tuple {x_1, x_2, \ldots, x_n}$ and $y = \tuple {y_1, y_2, \ldots, y_n}$.

\(\displaystyle x\) \(\ne\) \(\displaystyle y\)
\(\displaystyle \leadsto \ \ \) \(\, \displaystyle \exists k \in \closedint 1 n \, \) \(\displaystyle x_k\) \(\ne\) \(\displaystyle y_k\)
\(\displaystyle \leadsto \ \ \) \(\displaystyle \size {x_k - y_k}\) \(>\) \(\displaystyle 0\) Definition of Absolute Value
\(\displaystyle \leadsto \ \ \) \(\displaystyle \max_{i \mathop = 1}^n \size {x_i - y_i}\) \(>\) \(\displaystyle 0\)
\(\displaystyle \leadsto \ \ \) \(\displaystyle \map {d_\infty} {x, y}\) \(>\) \(\displaystyle 0\) Definition of $d_\infty$

So axiom $M4$ holds for $d_\infty$.