# Combination Theorem for Continuous Mappings/Metric Space/Minimum Rule

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## Theorem

Let $M = \struct {A, d}$ be a metric space.

Let $\R$ denote the real numbers.

Let $f: M \to \R$ and $g: M \to \R$ be real-valued functions from $M$ to $\R$ which are continuous on $M$.

Let $\min \set {f, g}: M \to \R$ denote the pointwise maximum of $f$ and $g$.

Then:

- $\min \set {f, g}$ is continuous on $M$.

## Proof

Let $a \in M$ be arbitrary.

From Min Operation Representation on Real Numbers

- $\min \set {x, y} = \dfrac 1 2 \paren {x + y - \size {x - y} }$

Hence:

- $\min \set {\map f x, \map g x} = \dfrac 1 2 \paren {\map f x + \map g x - \size {\map f x - \map g x} }$

From Difference Rule for Continuous Mappings on Metric Space:

- $\map f x - \map g x$ is continuous at $a$.

From Absolute Value Rule for Continuous Mappings on Metric Space:

- $\size {\map f x - \map g x}$ is continuous at $a$.

From Sum Rule for Continuous Mappings on Metric Space:

- $\map f x + \map g x$ is continuous at $a$

From Difference Rule for Continuous Mappings on Metric Space:

- $\map f x + \map g x - \size {\map f x - \map g x}$ is continuous at $a$

From Multiple Rule for Continuous Mappings on Metric Space:

- $\dfrac 1 2 \paren {\map f x + \map g x - \size {\map f x - \map g x} }$ is continuous at $a$.

As $a$ is arbitrary:

- $\min \set {f, g}$ is continuous on $M$.

$\blacksquare$

## Sources

- 1975: W.A. Sutherland:
*Introduction to Metric and Topological Spaces*... (previous) ... (next): $2$: Continuity generalized: metric spaces: Exercise $2.6: 14$