Coproduct of Free Monoids
Theorem
Let $\mathbf {Mon}$ be the category of monoids.
Let $\map M A$ and $\map M B$ be free monoids on sets $A$ and $B$, respectively.
Let $A \sqcup B$ be the disjoint union of $A$ and $B$.
Then the free monoid $\map M {A \sqcup B}$ on $A \sqcup B$ is the coproduct of $\map M A$ and $\map M B$ in $\mathbf {Mon}$.
Proof
By Coproduct is Unique, it suffices to verify that $\map M {A \sqcup B}$ is a coproduct for $\map M A$ and $\map M B$.
By the universal mapping property of $\map M A$, $\map M B$ and $\map M {A \sqcup B}$, we have the following commutative diagram:
$\quad\quad \begin {xy} <0em, 5em>*+{N} = "N", <-5em,0em>*+{\map M A} = "MA", <0em,0em>*+{\map M {A \sqcup B} } = "MAB", <5em,0em>*+{\map M B} = "MB", <-5em,-5em>*+{A} = "A", <0em,-5em>*+{A \sqcup B} = "AB", <5em,-5em>*+{B} = "B", "A";"MA" **@{-} ?>*@{>} ?*!/_.8em/{i_A}, "B";"MB" **@{-} ?>*@{>} ?*!/^.8em/{i_B}, "AB";"MAB" **@{-} ?>*@{>} ?*!/_.8em/{i_{A \mathop \sqcup B} }, "A";"AB" **@{-} ?>*@{>} ?*!/^.8em/{i_1}, "B";"AB" **@{-} ?>*@{>} ?*!/_.8em/{i_2}, "MA";"MAB" **@{-} ?>*@{>} ?*!/_.8em/{j_1}, "MB";"MAB" **@{-} ?>*@{>} ?*!/^.8em/{j_2}, "MA";"N" **@{-} ?>*@{>} ?*!/_.8em/{\bar f}, "MB";"N" **@{-} ?>*@{>} ?*!/^.8em/{\bar g}, "MAB";"N" **@{--} ?>*@{>} ?*!/_.8em/{\bar h}, \end{xy}$
Here (in the notation for free monoids):
- $j_1 = \overline {\paren {i_{A \mathop \sqcup B} \circ i_1} }$
- $j_2 = \overline {\paren {i_{A \mathop \sqcup B} \circ i_2}}$
and $i_1$, $i_2$ are the injections for the coproduct.
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Sources
- 2010: Steve Awodey: Category Theory (2nd ed.) ... (previous) ... (next): $\S 3.2$: Example $3.5$