Definition:Absolute Continuity
Definition
Real Function
Let $I \subseteq \R$ be a real interval.
A real function $f: I \to \R$ is said to be absolutely continuous if and only if it satisfies the following property:
- For every $\epsilon > 0$ there exists $\delta > 0$ such that the following property holds:
- For every finite set of pairwise disjoint closed real intervals $\closedint {a_1} {b_1}, \dotsc, \closedint {a_n} {b_n} \subseteq I$ such that:
- $\ds \sum_{i \mathop = 1}^n \size {b_i - a_i} < \delta$
- it holds that:
- $\ds \sum_{i \mathop = 1}^n \size {\map f {b_i} - \map f {a_i} } < \epsilon$
- For every finite set of pairwise disjoint closed real intervals $\closedint {a_1} {b_1}, \dotsc, \closedint {a_n} {b_n} \subseteq I$ such that:
Measure
Let $\struct {X, \Sigma}$ be a measurable space.
Let $\mu$ and $\nu$ be measures on $\struct {X, \Sigma}$.
We say that $\nu$ is absolutely continuous with respect to $\mu$ and write:
- $\nu \ll \mu$
- $\ds \forall A \in \Sigma : \map \mu A = 0 \implies \map \nu A = 0$
Signed Measure
Let $\struct {X, \Sigma}$ be a measurable space.
Let $\mu$ be a measure on $\struct {X, \Sigma}$.
Let $\nu$ be a signed measure on $\struct {X, \Sigma}$.
Let $\size \nu$ be the variation of $\nu$.
We say that $\nu$ is absolutely continuous with respect to $\mu$ if and only if:
- $\size \nu$ is absolutely continuous with respect to $\mu$.
We write:
- $\nu \ll \mu$
Complex Measure
Let $\struct {X, \Sigma}$ be a measurable space.
Let $\mu$ be a measure on $\struct {X, \Sigma}$.
Let $\nu$ be a complex measure on $\struct {X, \Sigma}$.
Let $\size \nu$ be the variation of $\nu$.
We say that $\nu$ is absolutely continuous with respect to $\mu$ if and only if:
- $\size \nu$ is absolutely continuous with respect to $\mu$.
We write:
- $\nu \ll \mu$
Also see
- Results about absolute continuity can be found here.