# Definition:Convergent Product/Arbitrary Field

## Definition

Let $\struct {\mathbb K, \norm {\,\cdot\,} }$ be a valued field.

### Nonzero Sequence

Let $\sequence {a_n}$ be a sequence of nonzero elements of $\mathbb K$.

The infinite product $\ds \prod_{n \mathop = 1}^\infty a_n$ is convergent if and only if its sequence of partial products converges to a nonzero limit $a \in \mathbb K \setminus \set 0$.

### Arbitrary Sequence

Let $\sequence {a_n}$ be a sequence of elements of $\mathbb K$.

The infinite product $\ds \prod_{n \mathop = 1}^\infty a_n$ is convergent if and only if:

there exists $n_0 \in \N$ such that the sequence of partial products of $\ds \prod_{n \mathop = n_0}^\infty a_n$ converges to some $b \in \mathbb K \setminus \set 0$.

The sequence of partial products of $\ds \prod_{n \mathop = 1}^\infty a_n$ is then convergent to some $a \in \mathbb K$.

The product is said to be convergent to $a$, and one writes:

$\ds \prod_{n \mathop = 1}^\infty a_n = a$

A product is thus convergent if and only if it converges to some $a \in \mathbb K$.

## Divergent Product

An infinite product which is not convergent is divergent.

### Divergence to zero

If either:

there exist infinitely many $n \in \N$ with $a_n = 0$
there exists $n_0 \in \N$ with $a_n \ne 0$ for all $n > n_0$ and the sequence of partial products of $\ds \prod_{n \mathop = n_0 + 1}^\infty a_n$ converges to $0$

the product diverges to $0$, and we assign the value:

$\ds \prod_{n \mathop = 1}^\infty a_n = 0$