# Definition talk:Differentiable Mapping

I'm tempted to move some of this into Definition:Derivative so as to match the rest of the exposition of this subject. As I planned it, "Differentiable" was a minor (but important) side-issue, i.e. a condition under which the derivative was valid. Same applies to "analytic". The real meat of the issue is that thing called the Derivative.

I'll get round to it later, I've got a busy week this week, I might not get much done. --prime mover (talk) 06:39, 27 January 2009 (UTC)

... okay, I think it still needs work: the definition that I learned was that the domain of $\C$ on which the function is defined needs to be a Definition:Region (in the topological sense of being open). I may also introduce the concept of a neighbourhood. As I say, it's all in the plan - I'll be coming back to this entire area and tightening it up in time. --prime mover (talk) 07:46, 27 January 2009 (UTC)

## Closed Interval

Where did your definition of differentiability on a closed interval come from? I don't believe it necessarily holds at the end points.

Define $f: \R \to \R$ as:

- $\forall x \in \R: f(x) = \begin{cases} x & : x \le 1 \\ 1 & : 1 < x < 2 \\ x - 1 & : x \ge 2\end{cases}$

Unless I'm not mistaken, at the endpoints of $[1..2]$, $f(x)$ has a different derivative depending on whether you come at it from the left or right. As such, that means $f$ does not have a derivative at those points.

Intuitively, you can't find the derivative of a curve where there's a sharp corner in it (like here). So you can't say that $f$ is diff'able at those points. Or am I missing something crucial? --prime mover 14:30, 7 December 2011 (CST)

- I got it from Larson. Even though $f$ doesn't have a derivative at the end points, it has one sided derivatives. It's the same problem with continuity on a closed interval, no?:

- Define $g: \R \to \R$ as:

- $\forall x \in \R: g(x) = \begin{cases} -\pi & : x \le 1 \\ 1 & : 1 < x < 2 \\ \text{a billion} & : x \ge 2\end{cases}$

- $g$ is continuous on $[1..2]$, according to the definition here, even though it's not continuous at the endpoints. --GFauxPas 14:43, 7 December 2011 (CST)

- Continuous yes, but not
*differentiable*. I might be prepared to grant you semi-differentiable, which will need a separate page. Sorry, but I'm prepared to stick my neck out and say I believe Larson is over-simplifying to the point of being incorrect. His definition leads to contradictions. - Anyone else care to join in on this one? --prime mover 14:51, 7 December 2011 (CST)
- It's not my intent to defend nor to attack Larson's views, I'm just trying to fill in what "differentiable on $[a..b]$" means (such as here). I don't have any emotional attachment to the issue. Is the real function: $h(x) = \sqrt{1-x^2}$, $0 \le x \le 1$ differentiable on $[0..1]$? --GFauxPas 15:58, 7 December 2011 (CST)
- A slightly broader perspective has led me to think of differentiability as a local property. As such, we need open neighbourhoods to work with. Therefore it may be (in a formal sense) void to talk about differentiability without referring to the topology. Paradoxically, I think it might be the case that a function is diffable on $[0..1]$ despite not being so on $[0..1+\epsilon)$ for any $\epsilon >0$. But I may be stretching it. --Lord_Farin 16:25, 7 December 2011 (CST)
- From the point of view of the original source work, from which Primitives which Differ by Constant originally came, "differentiable on $[a..b]$" wasn't used. That latter came with a later edit. I have put that proof back to where it originally was. As it stands we have a definition for differentiability on an open interval which is logically consistent, and a definition for diff'ability on a closed one, which can only be applied in one direction. All my experience in real analysis has given me this "common sense" approach to work with.
- Clearly there is a wider context in which diffability on a closed interval makes sense - but on the real number line (which is where we are limited to until we properly develop the mathematics behind these more advanced, more abstract concepts) we can only have the definitions as they apply on that line.
- Larson may well have a specific reason for needing to define the derivative on the endpoint of an interval - but on the other hand he may well just be loose. Without seeing it and studying where he's going with it I can't tell.
- LF: feel free to add an analysis of the paradoxical result above.
- As for $h(x) = \sqrt{1-x^2}$, it's diffable at $0$ but not at $1$ because it's not defined for $x > 1$.--prime mover 16:51, 7 December 2011 (CST)

- A slightly broader perspective has led me to think of differentiability as a local property. As such, we need open neighbourhoods to work with. Therefore it may be (in a formal sense) void to talk about differentiability without referring to the topology. Paradoxically, I think it might be the case that a function is diffable on $[0..1]$ despite not being so on $[0..1+\epsilon)$ for any $\epsilon >0$. But I may be stretching it. --Lord_Farin 16:25, 7 December 2011 (CST)

- It's not my intent to defend nor to attack Larson's views, I'm just trying to fill in what "differentiable on $[a..b]$" means (such as here). I don't have any emotional attachment to the issue. Is the real function: $h(x) = \sqrt{1-x^2}$, $0 \le x \le 1$ differentiable on $[0..1]$? --GFauxPas 15:58, 7 December 2011 (CST)

- Continuous yes, but not

I am going to sleep first, but in the mean time think of it in a similar manner as continuity on a closed interval, cf. the function $g$ above for an example with continuity for what might seem paradoxical. --Lord_Farin 16:55, 7 December 2011 (CST)

### Problem...

1. I agree with considering vector-valued functions as ordered tuples.

2. I was going to add differentiability $\R^n \to \R^m$ here so I can define the Jacobian, and then do differentials much more simply (in the standard way) in this case. There's a slight problem that should be resolved first -- the operator $\nabla$ is used to define differentiability, but $\nabla f$ isn't defined in the first place until we know $f$ is differentiable. The definition, in effect, should be asserting the existence of $\nabla f$, not of $\Delta f(\mathbf x)$. If there's no objection I'll reorder this to avoid circularity, and change it in accordance with {improve} thingy.

- I have completely refactored the Differentiable page to allow more flexibility in rearranging stuff as appropriate. (I have a plan to add a separate page Differentiable/Point which will specifically gather all the various "Differentiable at a Point" definitions into one place, for example).
- Not quite sure what you're getting at here, so probably best if you paste something up and we can rearrange it as necessary once we see what you've got. --prime mover (talk) 08:28, 30 September 2012 (UTC)

## Rename to "Differentiable Mapping"?

Much like Definition:Smooth is a dismabiguation page, should Definition:Differentiable be one too, given that there are other differentiable things? --barto (talk) 06:03, 8 August 2017 (EDT)

- Yes, I would say so. This is a movement that has been in progress for a longer time. In my experience, it always adds to clarity to add the noun to the adjective. Feel free to tag with Rename if you are overwhelmed with the work required. — Lord_Farin (talk) 11:21, 20 August 2017 (EDT)

It's done... finally. In the process of doing it, I found Definition:Differentiable Mapping/Functional which is ripe for redirection. Also, the structure now is quite unclear and surprising on click-through. I would actually feel more comfortable if all pages were split and grouped on the disambiguation page. Or? — Lord_Farin (talk) 14:07, 23 August 2017 (EDT)

- The trouble with disambig pages is that it's too easy to link to the wrong page through lazy linking ... but OTOH the whole structure of differentiation is a mess already so I don't know what else to do. --prime mover (talk) 15:12, 23 August 2017 (EDT)

- I completely agree, including that I don't know what else to do. The more complete
*(there are more definitions coming, such as Definition:Differentiable Mapping between Manifolds)*the more messy this page becomes... Short pages are cleaner, but we do want to emphasize the analogy between the definitions.

- I completely agree, including that I don't know what else to do. The more complete

- Difficult. If we don't transclude all definitions of differentiable mappings on one page, the best alternative I see is to make Definition:Differentiable Mapping yet another disambig page. --barto (talk) 15:30, 23 August 2017 (EDT)

Seconded. — Lord_Farin (talk) 05:38, 9 September 2017 (EDT)