Definition talk:Image (Relation Theory)/Mapping/Element
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is the image of an element an element or a set (singleton)?
I think there is an inconsistency in
- $\Img s = \map f s = \bigcup \set {\ldots}$
- $\map f s$ should be an element the codomain of $f$, but
- $\bigcup \set {\ldots}$ is a set of such elements.
Although, it's specified under that the value is unique and well-defined, the definition isn't coherent in respect to the typing.
Is the part '$= \bigcup \set {\ldots}$' really needed / adding some valuable info here? Austrodata (talk) 17:50, 20 February 2025 (UTC)
- You could well have a point.
- The $\bigcup$ came in here:
- Not sure why. We have cause to mistrust the exposition generated from the Takeuti and Zaring work.
- This may add some context as to why it was originally defined as a set in the first place:
- I'll give it some thought in due course, but in the meantime leave it open to others to weigh in. --prime mover (talk) 20:12, 20 February 2025 (UTC)
- I see. Thanks for the investigation.
- This must be definition 6.11 to 6.14, p26-27, 2nd ed. of Takeuti and Zaring.
- As far as I can understand they are consistent about this but only define $A'b$ as a set, noting that it is a singleton (but this book is very hard to read for me, partly because it contains a lot of unusual notation).
- That said, I've done a quick check among the books I've at hand and I only found one which explicitly define the concept of 'the image of an element under a function': Goldrei, Classic Set Theory for Guided Independent Study, 1996. The other ones don't bother with this and only define the image of a subset. Austrodata (talk) 21:40, 20 February 2025 (UTC)
- I wonder whether to shrug it aside with an "also defined as" page which defines it as an element rather than as a set, and casually dismiss it by saying something like "$\mathsf{Pr} \infty \mathsf{fWiki}$ may use either convention, and which one is clear from its context" or something, noting that by definition of a function, the image is a singleton, as you allude to above.
- Alternatively we define it as an element, but then define the singleton image as the image set.
- But it would be a shame to lose the compatibility of the definition of the image of an element under a function with that under a relation. --prime mover (talk) 22:37, 20 February 2025 (UTC)