Derivative of Hyperbolic Secant of a x

From ProofWiki
Jump to navigation Jump to search

Theorem

$\map {\dfrac \d {\d x} } {\sech a x} = -a \sech a x \tanh a x$


Proof

\(\ds \map {\dfrac \d {\d x} } {\sech x}\) \(=\) \(\ds -\sech x \tanh x\) Derivative of $\sech x$
\(\ds \leadsto \ \ \) \(\ds \map {\dfrac \d {\d x} } {\sech a x}\) \(=\) \(\ds -a \sech a x \tanh a x\) Derivative of Function of Constant Multiple

$\blacksquare$


Also see