Directed Suprema Preserving Mapping at Element is Supremum

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Theorem

Let $\struct {S, \vee, \wedge, \preceq}$ and $\struct {T, \vee_2, \wedge_2, \precsim}$ be bounded below continuous lattices.

Let $f: S \to T$ be a mapping such that

$f$ preserves directed suprema.

Let $x \in S$.


Then:

$\map f x = \sup \set {\map f w: w \in S \land w \ll x}$


Proof

By definition of continuous:

$x^\ll$ is directed

and

$\struct {S, \vee, \wedge, \preceq}$ is up-complete

and

$\struct {S, \vee, \wedge, \preceq}$ satisfies the Axiom of Approximation.

By definition of mapping preserves directed suprema:

$f$ preserves the supremum of $x^\ll$.

By definition of up-complete:

$x^\ll$ admits a supremum.

Thus

\(\ds \map f x\) \(=\) \(\ds \map f {\map \sup {x^\ll} }\) Axiom of Approximation
\(\ds \) \(=\) \(\ds \map \sup {f \sqbrk {x^\ll} }\) Definition of Mapping Preserves Supremum: Subset
\(\ds \) \(=\) \(\ds \map \sup {f \sqbrk {\set {w \in S: w \ll x} } }\) Definition of Way Below Closure
\(\ds \) \(=\) \(\ds \sup \set {\map f w: w \in S \land w \ll x}\) Definition of Image of Subset under Mapping

$\blacksquare$


Sources